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1L.解：在△ACQ中，因为M,N为AC,AQ的中点，DHBBBB所以MN/1CQ,所以CN与QM共面，所以①正确：由'ADw='x-w,因为N到平面ABCD的距离为定值，，且△ADM的面积为定值三，所以三棱锥A-DMN的体积跟入的4取值无关，所以@E确：当2=，40=子可得M2=分4Q=4+40=1+6-需.925取AD,AD,的中点分别为N,E,连接EN,EM,则EM?=MN2+EN2=+1d在角三角影0中，:=E+-+-君则AM2+QM2>AQ,所以AM⊥QM不成立，所以③不正确.当入=时，取岩=光达接HC,则H014C,又4C1AC所以H0114C3所以A,M,C,H,Q共而，即过A,Q,M三点的止方体的截面为ACIg,ACHQ是等腰梯形，且QH=7AC=4_4w2+213所以平面截正方体所得截面的周长为1=5+号+2×小+),所以④正确：3所以正确的命题是①②④，故选：B.

Dear fellows,We are proud to announce that Teens Today will be starting a new column featuring "Technology andHumanity"this term!And we are expecting your theme-related articles.The contributions should cover your authentic experiences with technology and unique insight into how technology isreshaping your lives.They are required to be original and within 300 words.Please submit your articles before 18th eachmonth to me.Any contributor whose works appear in our column will be awarded a certificate of acceptance and 50 inprize money.Looking forward to your works!Li Hua