21.解:f(x)的定义域为(0,+∞)f(x)=f(x)在(0,c)上单调递减,在(c,+∞)上单调递增:若a>0,当a=e时,f(x)在(0,+∞)上单调递增当a>e时,f(x)在(e,a)上单调递减,在(O.e),(a,+∞)上单调递增当0 cm)()上单圆减在(Q)5分当0 0,q(a)在(0,2)上单调递增,g(a)>q(0)=0g'(a)>0,g(a)在(0,2)上单调递增,g(a)>g(0)=010分>1+a而a-2<0f(e)<(a-2)(a+1)=a2-a-2f(e)+2
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