Cl: N: CI16.(1)①氢气(1分):C(1分)②NH4Cl+2HCl电解==NCl3+3H2↑(2分)(2)氢气(1分)NaOH(1分)阴极(1分)2H2O4e=O2↑+4H+(1分)阳(1分)【解析】(1)①气体A是H2,NCl3的电子式为C:电解②电解的化学方程式为NHCl+2HCl=NCl2+3H2↑(2)根据图可知,电极Ⅹ附近生成了氧气和硫酸,说明发生了氧化反应,所以电极X为阳极,电极Y为阴极气体b为氢气,A为氢氧化钠,电极X上发生的电极反应为2H2O-4e=O2↑+4H,阴极上生成氢气同时阴极附近生成NaOH,溶液中的钠离子通过离子交换膜N进人阴极区,因此离子交换膜N为阳离子交换膜

第二节书面表达Dear Henry,Im Li Hua from your English speaking class lastterm. I m writing to ask for your helpNow I am preparing to attend MUN next weckHowever,have some difficulty with concepts andexpressions of the current affairs and speech skills. Iwonder if I can borrow your Dictionary of englishMedia. which you presented in class. Furthermore.I amnot quite sure about how to make a convincing andpersuasive speech at MUN. Could you be so kind as to giveme some advice?I know you have a very busy schedule, but I'd be verygrateful if you could spare some time to give me face-to-acc instructions. Thank you for your kindnessI'm looking forward to your replyYoursLi Hua

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