3B【解析】在0~L过程中,导线框中磁通量增大,由楞次定律知,感应电流方向沿顺时针方向,1=By,t=x,则=Rx;在L~2过程中,磁通量先增大后减小由楞次定律知,感应电流方向先沿顺时针方向,后沿逆时针方向,且电流大小随位移x均匀变化;在2L~3L过程中,导线框中磁通量减小,由楞次定律知,感应电流方向沿逆时针方向,由法拉第电磁感应定律和闭合电路欧姆定律可知,导线框中的电流随位移均匀减小到零,B正确。

解题导语】这是一篇说明文。文幸讲述了书香环境对于孩子成长的好处32B推理判断题。根据第二段中“ Radiation effect is a situationwhere children grow up around books, but they don't readbooks. But somehow books benefit then, even thoughthey don't read them as much as their parents wish themo”可知,辐射效应在本文中指在书香环境中长大的孩子虽然他们没有像父母期待的那样读那么多的书,但他们仍然从书中受益良多。由此推断出,书香环境对青少年的良好影响,故选B这A理判断题。根据第三段中“ If we grow up in a house,ina home where parents enjoy books, where books are givenas birthday presents and valued, this is something thatbecomes a part of our identity and gives us this lifelongurge to always come close to books and read more than we I则ld呵可知,如果我们生长在父母热爱书、珍惜书的家庭中,这将成为我们认知中的一部分,让我们终身都有接近书,多读书的渴望、故选A现点态度题,根据最后一段中“ So keep shelves piled with30y所以书柜里装满书吧,由此可知,作者对于书香环境是支持的,故选DsC主旨大意题,根据全文的大意,尤其是第一段中“weknow that reading is good for children. Now, a new studysuggests that just being around books has its benefits. "pJ,本文主要讲述了书香环境对孩子成长的好处。故选

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