第二节书面表达【写作思路】根据试题要求,考生需要写一篇记叙文,记述身边一位值得尊敬和爱戴的人。首先考生需要介绍自己最尊敬和爱戴的人是谁,简单地介绍一下他(她)。然后,陈述为什么他(她)值得尊敬和爱戴。最后,可以对前文进行一个总结,使文章结构严谨。本文的写作重点在"尊敬和爱戴的原因",考生可围绕这个要点适当拓展,从性格特点、处事风格等方面展开写作。【范文赏读】The most beloved and respected person around me is my teacher, Ms LiThough she has been teaching English for twenty years, she is still passionateabout teaching. She is kind and considerate towards us just like our dear motherWe all respect her because she always tries new ways to make her classes livelyand interesting. Hardworking and knowledgeable, she is one of the best teachersin our school. When we have a problem, we will turn to her for help. She alwaystalks to us patiently and helps us to find a solution. In our eyes, she is not onlyour teacher, but also our best friend. Those are why she deserves our respect【亮点词句】亮点词汇: beloved, respected, be passionate about, be consideratetowards, turn to sb. for help, in one's eyes亮点句式:Why引导的表语从句( why she deserves our respect)

8.(15分)(1)-746kJ(2分)ABC(2分)5(2)①<(1分)该反应放热,温度升高,平衡逆向移动,N的物质的量减小(2分)②0.032mol·Ll·min-(2分)4(2分、320③60%(1分)G小于(1分)甲中温度低,因此反应物转化率大压强变化大(2分)【解析】(1)已知:I.N2(g)+O2(g)、2NO(g)△H=+180kJ·mol',Ⅱ.2CO(g)+O2(g)2CO2(g)△H=-566kJ·mol-,根据盖斯定律一I得,2CO(g)+2NO(g)N2(g)+2CO2(g)△H=-746kJ·mol-。该反应是气体体积减小的反应,在恒温恒压密闭容器中进行该反应时,混合气体的密度、平均摩尔质量不再改变,均说明反应达到平衡状态,A、B项正确;反应过程中NO的分压不断减小,CO2的分压不断增大,二者分压之比不再改变说明反应达到平衡状态,C项正确;断裂1molN=N键的同时断裂4molC=O键描述的均是逆反应方向,D项错误。(2)①甲、乙两容器中起始加入反应物的物质的量相同、起始压强相同,该反应为放热反应,温度升高,平衡逆向移动,N2的物质的量减小,故T1

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