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2022-2023学生双语报浙教版初一下答案

作者:admin 时间:2022年10月15日 阅读:74 评论:0

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2022-2023学生双语报浙教版初一下答案

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Dear fellow students,Recently,natural disasters,such as droughts,floods,landslidesand so on have been frequently reported all over the country,causing deaths and injuries.As is known to each of us,this monthmountain torrents caused by sudden rainstorm in Pengzhou tookseven lives and left dozens severely injured.Therefore,we appealto all of you to care more about safety during summer vacation.First and foremost,it is strongly suggested that you stay awayfrom rivers and streams,especially during the flooding season insummer,while swimming pools definitely serve as a better choice,where lifeguards there can offer you a hand in case of anyemergency.In the meantime,it's not a brilliant idea to go hikingor cycle in mountains,since no one knows when and where asudden landslide may be to blame for another tragedy.Above all,with COVID-19 pandemic still in full swing,there is no need toplan for frequent travelling,which may increase the risk of beinginfected by the virus.It's hard to imagine what would happen if we take a blind eyeto the possible dangers,and only with raised awareness of safetycan each day of the summer vacation be full of joy and blessing.Student Union

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16.【答案】将Fe3+、Co3+还原C1O3-+6Fe2++6H+=C1-+6Fe3++3H20使Fe3+和A13+沉淀完全CaF2和MgF2蒸发浓缩冷却结晶F+H2OHF+OHCo3O4(或Co0Co203)【详解】(1)、浸出过程中,Co2O3、Fe2O3与盐酸、Na2SO3发生反应,Co2O3转化为Co2+,Fe2O3转化为Fe2+,Co、Fe元素化合价降低,则S元素化合价升高,SO32-转化为SO42-,故答案为将Fe3+、Co3+还原:(2)、NaCIO3加入浸出液中,将Fe2+氧化为Fe3+,ClO-被还原为Cl-,反应的离子方程式为:ClO3-+6Fe2++6H+=Cl-+6Fe3++3H20-;(3)根据工艺流程图结合表格中提供的数据可知,加Na2CO3调pH至5.2,目的是使F©3+和AI3+沉淀完全。滤液1中含有的金属阳离子为Co2+、Mn2+、Mg2+、Ca2+等,萃取剂层含锰元素,结合流程图中向滤液1中加入了NaF溶液,知沉淀IⅡ为MgF2、CaF2:(4)、经过操作I由溶液得到结晶水合物,故除题中已知过程外,操作I还包括蒸发浓缩、冷却结晶:(6)、整个受热过程中只产生水蒸气和C02气体,5.49gCoC2042H20为0.03mol,固体质量变为4.41g时,质量减少1.08g,恰好为0.06molH20的质量,因此4.41g固体为0.03 mol CoC204。依据元素守恒知,生成n(C02)-0.06mol,m(C02)-0.06mol×44gmol=2.64g。而固体质量由4.41g变为2.41g时,质量减少2g,说明290-320℃内发生的不是分解反应,参加反应的物质还有氧气。则参加反应的m(02)=2.64g-2g0.64g,n(02)=0.02mol,n(CoC204):n(02):n(C02)=0.03:0.02:0.06=3:2:6,依据原子守恒,配平化学方程式3C0C,0,+202290-~320℃C0,0,+6C02,故290-320℃温度范围,剩余固体物质的化学式为Co3O4或Co0Co2O3。

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