第二节读后续写( One possible version)Fliss immediately took the purse to the local police station with Molly. When they arrivedFliss tied Molly to a fireplug outside and went in herself. She handed the purse to a police officerand explained everything. Greatly touched, he shook her hand and thanked her for doing her duty,promising that he would do his best to find the owner Fliss felt reassured and went back withMolly. The next day, a journalist called to make an appointment for an interview.When the journalist came, they two were on the beach. The journalist was surprised to findthat Molly was picking up litter, following her master. Fliss told the journalist it was on the wayto collecting litter that Molly had found the purse. Hearing this, Molly stopped, wagging her tailas if she understood the whole situation. Having learned about the whole story, the journalist gotto know what they did to protect the local beach. Surprised and impressed, the journalist tooksome pictures. The next day they were on the front page of the newspaper. A minor action couldmake wonders!(162 words)

28.(1)2O2光302(1分)(2)①La2O3(s)+2C0(g)=1a20s)+2CO2(g)△H=+31k·mol②C(各2分)(3)① K(B)=K(C):>(各1②,9(2分)(4)>(2分)(5)①2H2O+2e=H2↑+2OH(1分②8:3(2分)解析:(1)由反应机理可知,臭氧在光的作用下分解生成氧气和氧原子氧原子与一氧化氮反应生成二氧化氮二氧化氮分子间反应生成一氧化氮和氧气,总反应的化学方程式为20WQ(2)①根据总反应与分步反应的关系可知,总反应一反应I=反应Ⅱ,则反应Ⅱ的热化学方程式为Ia2O3(s)2CO(g)La2O(s)+2CO2(g)△H=+31kJ·mol-l。②判断图像正确与否主要看三个方面反应1和Ⅱ的先后顺序,因为La2O为催化剂,所以先发生反应Ⅱ是否符合总反应以及反应!和的放吸热特点;根据反应速率公式可知反应的速率慢即活化能大,C项正确。(3)①由图可知,温度升高NO2的转化率降低,故该反应为放热反应,温度越高,平衡常数越小A、B、C三点温度高低为T(A) K(B)=K(C);300℃、P2条件下,E点未达到平衡,且此时NO2的转化率小于平衡时NO2的转化率,则E点的vE>0.5②根据三段式法计算平衡时各物质的分压分别为pa2=.P2,a2=4,52,=15,例O=4,5,×故Kpn2×x24p2(4)由题给数据可知,温度为T时,c(NO2)=0;2mo·L-1、c(NO)=0.4mol·L-1,c(O2)0.2mol·L-1,平衡常数K=0.42×0.2/0.22=0.8;达到平衡状态时v=,则有k正c2(NO2)=k证(NO)·c(O2);当温度变为T2,达到平衡状态时同样有k/k=2(NO)·c(O2)/2(NO2),此时k正/k逆=c2(NO)·c(O2)/(2(NO2)=1>0.8,说明改变温度后平衡正向移动,由于该反应的△H>0,所以(5)①根据装置图,a极为阴极,电极反应式为2H2O+2c—H2↑+2OH,b极为阳极,NO气体发生氧化反应生成硝酸和亚硝酸。②根据原子守恒:n(NO)+n(NO2)=3mol+0.1mol-0.2mol·L-1×10L=1.1mol,根据电子守恒:0.1mol×1+[n(NO)-0.1mo×3+n(NO2)×1=2.4L·m21×2.解得,nNOD8m00.3 mol, V(NO): V(NO2)=n(NO): n(NO2)=0. 8 mol 0 3 mol=8: 3.

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