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2021-2022英语周报高考综合41期答案

作者:admin 时间:2022年10月09日 阅读:57 评论:0

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读后续写Once we reached the kitchen. he asked me what wewanted to tell him everything,but didnt want to disappoint him the way I had disappointed my parents. Furthermore, mymother's comment about his surgery was on my mind. So i shook my head At that moment, myfather came into the kitchen. My grandfather looked at him, concerned, and then asked the samequestion. My father froze momentarily and then assured him with a big smile that i was just tiredThen he grabbed my arm to drag me away.at my grandfather stopped him with a look, and gently laid a hand on my arm. Suddenlycouldnt contain my feeling and burst into tears. I looked at him and sobbingly said, "I don'twant to make sweets. I don' t want to run the store. "My grandfather stood quietly for a moment,absorbing this; then he looked at me and said simply, "Then you will not make sweets. "Butwhat else can she do? "my father said, frustrated"Well, she's an excellent storyteller. I imaginshe'll be a writer, "my grandfather said

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19.(13分)(1)球形(1分)(2)b>d>a>c(1分)(3)电子从较高能级的激发态跃迁到较低能级的激发态乃至基态时,常以光的形式释放能量而形成焰色反应(2分)(4)sp3(1分)4(1分)(5)①498kJ·mol1(1分)②11454k·mol1(1分)Ca原子失去一个电子后变成Ca+,带正电荷,较难失去第二个电子(1分)③>(1分)Mg2+半径小于Ca2半径,故MgO的晶格能大(1分)④合224N×1010r(2分)【解析】(1)基态钙原子占据最高能级的核外电子的电子云轮廓图形状为球形。(2)[Ar]3d24s2为基态钛原子的电子排布式,能量最低[Ar]3d34s为1个电子由4s跃迁到3d能量稍高;[Ar]3d为2个电子由4s跃迁到3d,能量再高一些;[A]3d4p2为2个电子跃迁,其中1个跃迁到3d,1个跃迁到4p,能量最高。故能量由大到小的顺序为b>d>a>c(3焰色反应的微观原因为电子从较高能级的激发态耿迁到较低能级的激发态乃至基态时,常以光的形释放能量而形成焰色反应。4硅晶体中硅原子的杂化方式为sp3,配位数为4(5)①由图1中数据可知,O=O键的键能为498kJ·mol-1。②由图1中数据可知,钙的第二电离能为1145.4kJ·mhol,钙的第二电离能远大于钙的第一电离能的原因为Ca原子失去一个电子后变成Ca+,带正电荷,较难失去第二个电子。③由图1中数据可知,CaO的晶格能为3401kJ·mol-,则MgO的晶格能>3401kJ·mol-,原因为Mg2+半径小于Ca2半径,故MgO的晶格能大。④设晶胞棱长为acm,每个CaO晶胞中含有4个Ca2和4个0,o=22y!原得a=/224则Ca2的半径为(1×/22×1010-r)pm。

2021-2022英语周报高考综合41期答案

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