18.解:(1)不合理从散点图上看:①A组数据呈正相关,B组数据呈负相关两部分数据的变化趋势明显不同,不适合用同一个线性模型来拟合②20个样本点的分布比较分散,没有明显的沿直线分布的趋势故不适合用线性回归模型来拟合(以上给出了2种理由,答出任意一种或其他合理理由均可得分)(2)令2.1+0.8=5,得≈3.6令90.6-1.3=5,得≈65.8.由散点图可知,这种病毒的活性指标值先随温度升高而升高,到达一定温度后,开始随温度升高而降低,所以这种病毒适宜生存的温度范围是(3.6,65.8)(3)全部20组活性指标值的平均数为5=2分3=20×(14×18+6×23)=19.5因为∑y2=85×14+14×182=572,2=45×6+6×23=314所以全部20组活性指标值的方差为02-20y2)=1(5726+3440-19.53=78.25

第四部分写作第一节短文改错My father likes play chess and was alayingchampion when young. But he had no one to playwith after living with me A this new city."Finds newInFindplayers around to play with! "I suggested. He refusethem for different reasonsHe seemed to beto doso/itlonely, what made me worried.It occurred to me that how he could play chessonline. So I bought him the smartphone and taughtahim how to use the software. My father played sogood that he was soon acceptinga club. I feltacceptedpride of myself when his loneliness was gone.prouc

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