22.(1)AC(2)AD(3)CD(每空2分)解析:(1)本实验中碰撞必须对心碰撞,所以A正确;因为碰撞后两球都应该水平抛出离开斜槽,所以碰撞小球的质量应该大于被碰小球的质量,所以B错误;两小球碰撞后必须做平抛运动,所以C正确;从同一高度多次释放进行多次实验,有利于水平射程测量,即平均法减小实验误差,有利于实验结论得到验证,而不是使实验结论更具普遍性,所以D错误(2)本实验是验证碰撞过程动量守恒,即间接验证碰撞前瞬间系统动量之和等于碰撞后瞬间的系统动量之和相等,即mx1=m1x1+m2x'2,所以选A、D(3)本实验是验证碰撞过程动量守恒,即碰撞前瞬间系统动量之和等于碰撞后瞬间的系统动量之和相等,因此斜槽轨道光滑与否不受影响,所以A不入选;本实验相当于要测量小球平抛运动的初速度,因此应该减小平抛运动过程中空气阻力影响,小球尽可能质量大体积小,有利于减小空气阻力影响,所以B不入选;本实验要求碰撞后即做平抛运动因此C人选;之后保证平抛运动的时间相等才能确保水平距离与初速度等比例关系,故D入选

书面表达One possible version:NOTICEA sports meeting will be held in the playground of our school from next Thursday to FridayAs you know, the pressure of study is very heavy now, especially for those senior 3. So the purpose of the sports meeting is to letevery student get relaxed, as a result of which we students can live happily and heal thilyEveryone is welcome to take part in it. Those who perform excellently at the sports meeting will get prizes. But don' t take theresults so serously because taking part is more important than the result. Good luck to everyone!

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