8.BC【解析】从弹簧被压缩l到伸长1,弹簧的弹性势能变化量为零,根据动能定理得2 malsin0=mv2,可得v=√4gsnb,A错误;在x=位置,由图乙可知物块的加速度为a=258,根据牛顿第二定律得1 o,B正in 8-Fng s,解得F=2m8确;从0~1的过程弹簧弹性势能从某值减为零,物块的动能从零开始增大到某值,一定会出现弹簧弹性势能与物块动能相等的位置;从4~41过程物块的动能从某值先增大到最大值,再减小到零,弹簧的弹性势能从零开始增大到某值,也一定会出现弹簧弹性势能与物块动能相等的位置,C正确;在x=21处小物块加速度为零,速度最大,D错误

书面表达One possible version:NOTICEA sports meeting will be held in the playground of our school from next Thursday to FridayAs you know, the pressure of study is very heavy now, especially for those senior 3. So the purpose of the sports meeting is to letevery student get relaxed, as a result of which we students can live happily and heal thilyEveryone is welcome to take part in it. Those who perform excellently at the sports meeting will get prizes. But don' t take theresults so serously because taking part is more important than the result. Good luck to everyone!

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