17.(14分)(1) deane(f(1分)平衡烧瓶和分液漏斗中的压强,便于浓盐酸滴下(2分)(2)16H++2MnO+10C--2Mn2++5Cl2↑+8H2O(2分)(3)氯化锌发生水解生成Zn(OH)2,Zn(OH)2受热分解生成ZnO(2分,其他合理答案也给分)(4)碱石灰(1分)吸收多余的氯气和HCl,防止污染空气;防止空气中的水蒸气进入装置A(2分)(5)①100mL容量瓶、胶头滴管(2分)680②—%(2分)【解析】(1)装置D制备氯气,进入装置A前,Cl2需要干燥,但Cl2中的HCl杂质不需要除掉,装置C用于处理尾气,故装置的连接顺序为 hecabe(f);装置D中橡皮管的作用为平衡烧瓶和分液漏斗中的压强,便于浓盐酸滴下(2)装置D中反应的离子方程式为16H++2MnO+10C-2Mn2++5Cl2↑+8H2O(3)气体中有水蒸气杂质时,会导致氯化锌发生水解生成Zn(OH)2,Zn(OH)2受热分解生成ZnO(4)碱石灰不仅可以吸收尾气,同时还能防止空气中的水蒸气进入装置A(5)①配制100 mL Zncl2溶液需要用到的玻璃仪器有量筒、烧杯、玻璃棒、100mL容量瓶、胶头滴管,②根据关系式:ZnCh2~Zn2+~EDTA可知,ag试样中n(ZnO2)=bmoL×12.50×10-3L.×100ml=25.00m0.05bmol氯化锌的质量分数为0.05mol×136g:mol-1×100%=-%

书面表达: Dear Andrew,How nice to hear from you again i think it is natural for you not to get used tothe life there here i have some suggestions for youFirst of all, you should respect the local customs there and try to involveyourself in the natives' lives Just as the saying goes, When in Rome, do as theRomans do. Secondly, dont be afraid to communicate with American studentsand make friends with them. Friendship will bring you happiness. What's more, it'sbetter for you to join in more outdoor activities with your friends, which may helpyou relax and have fun Finally mind your own manners and modest and honestwhen getting along with your friendI do hope my suggestions will help May you adapt to your new life and enjoyyour stay there.Yours sincerely,Li H

以上就是英语周报 2018-20合（OT） 28答案，更多英语周报答案请关注本网站。

本文地址： http://www.ncneedu.cn/post/13565.html

文章来源：admin

版权声明：除非特别标注，否则均为本站原创文章，转载时请以链接形式注明文章出处。