28(爸曩⑩(共14分,每空2分)(1)2Mo(s)+302(g)=2Mo3(s)△H=△H3-2△H2-2△H1(2)①

P2>p②21,4(3)①ab②=(4)0.125考什么Q命题人考查化学反应原理的综合应用么考0(1)①MS2(s)—Mo(s)+S2(g)AH1②S2(g)+202(g)=2S02(g)△H2③2MS2(s)+7O2(g)==2MoO3(s)+4SO2(g)△H3根据盖斯定律,③-2×②2-2×①,整理可得2Mo(s)+302(g)=2MoO3(s)△H=△H3-2△H2-2△H1。(2)①根据图象可以得出,随着温度升高,转化率逐渐降低,说明平衡逆向移动,根据平衡移动原理,可以得出ΔH3<0;根据方程式特点,增大压强,有利于平衡正向移动,氧气平衡转化率增大,所以有p1>P2>P3②根据三段式法,可以得出:2MoS(s)+7O2(g)←-2Mo0(s)+4s02(g初始量/mol转化量/mo2.0平衡量/mol(2.2×)(2.214(3)根据反应特点,若向正反应方向移动,气体质量会增加,气体的密度会增大,密度不变则达到平衡状态,a项正确;反应体系中仅有S种气体,气体的相对分子质量-直保持不变,不能通过相对分子质量判断是否达到平衡状态,b项正确;MoS2为固体,增加MoS2的量,平衡不移动,c项错误。②根据平衡常数不变以及平衡常数表达式,可以得出充入S2(g),再次达到平衡时,S2(g)浓度不变。(4)根据三段式法,可以得出S2(g)+202(g)=2S02(g)初始量/mo1.01.50转化量/mob平衡量/mol1.05-2x21.5-2x=0.5,则x=0.5,S2的反应速率为b(S2)=0.5mo/(2L2 min)=0. 125 moL(L. min

第二节书面表达【写作思路】根据试题要求,考生需要写一篇记叙文,记述身边一位值得尊敬和爱戴的人。首先考生需要介绍自己最尊敬和爱戴的人是谁,简单地介绍一下他(她)。然后,陈述为什么他(她)值得尊敬和爱戴。最后,可以对前文进行一个总结,使文章结构严谨。本文的写作重点在"尊敬和爱戴的原因",考生可围绕这个要点适当拓展,从性格特点、处事风格等方面展开写作。【范文赏读】The most beloved and respected person around me is my teacher, Ms LiThough she has been teaching English for twenty years, she is still passionateabout teaching. She is kind and considerate towards us just like our dear motherWe all respect her because she always tries new ways to make her classes livelyand interesting. Hardworking and knowledgeable, she is one of the best teachersin our school. When we have a problem, we will turn to her for help. She alwaystalks to us patiently and helps us to find a solution. In our eyes, she is not onlyour teacher, but also our best friend. Those are why she deserves our respect【亮点词句】亮点词汇: beloved, respected, be passionate about, be consideratetowards, turn to sb. for help, in one's eyes亮点句式:Why引导的表语从句( why she deserves our respect)

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